Integrand size = 22, antiderivative size = 309 \[ \int \frac {x^2 (a+b x)^{5/2}}{(c+d x)^{3/2}} \, dx=\frac {2 c^2 (a+b x)^{7/2}}{d^2 (b c-a d) \sqrt {c+d x}}-\frac {5 (b c-a d) \left (63 b^2 c^2-14 a b c d-a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{64 b d^5}+\frac {5 \left (63 b^2 c^2-14 a b c d-a^2 d^2\right ) (a+b x)^{3/2} \sqrt {c+d x}}{96 b d^4}+\frac {\left (14 a c-\frac {63 b c^2}{d}+\frac {a^2 d}{b}\right ) (a+b x)^{5/2} \sqrt {c+d x}}{24 d^2 (b c-a d)}+\frac {(a+b x)^{7/2} \sqrt {c+d x}}{4 b d^2}+\frac {5 (b c-a d)^2 \left (63 b^2 c^2-14 a b c d-a^2 d^2\right ) \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{64 b^{3/2} d^{11/2}} \]
5/64*(-a*d+b*c)^2*(-a^2*d^2-14*a*b*c*d+63*b^2*c^2)*arctanh(d^(1/2)*(b*x+a) ^(1/2)/b^(1/2)/(d*x+c)^(1/2))/b^(3/2)/d^(11/2)+2*c^2*(b*x+a)^(7/2)/d^2/(-a *d+b*c)/(d*x+c)^(1/2)+5/96*(-a^2*d^2-14*a*b*c*d+63*b^2*c^2)*(b*x+a)^(3/2)* (d*x+c)^(1/2)/b/d^4+1/24*(14*a*c-63*b*c^2/d+a^2*d/b)*(b*x+a)^(5/2)*(d*x+c) ^(1/2)/d^2/(-a*d+b*c)+1/4*(b*x+a)^(7/2)*(d*x+c)^(1/2)/b/d^2-5/64*(-a*d+b*c )*(-a^2*d^2-14*a*b*c*d+63*b^2*c^2)*(b*x+a)^(1/2)*(d*x+c)^(1/2)/b/d^5
Time = 0.66 (sec) , antiderivative size = 229, normalized size of antiderivative = 0.74 \[ \int \frac {x^2 (a+b x)^{5/2}}{(c+d x)^{3/2}} \, dx=\frac {\sqrt {a+b x} \left (15 a^3 d^3 (c+d x)+a^2 b d^2 \left (-839 c^2-337 c d x+118 d^2 x^2\right )+a b^2 d \left (1785 c^3+637 c^2 d x-244 c d^2 x^2+136 d^3 x^3\right )-3 b^3 \left (315 c^4+105 c^3 d x-42 c^2 d^2 x^2+24 c d^3 x^3-16 d^4 x^4\right )\right )}{192 b d^5 \sqrt {c+d x}}+\frac {5 (b c-a d)^2 \left (63 b^2 c^2-14 a b c d-a^2 d^2\right ) \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{64 b^{3/2} d^{11/2}} \]
(Sqrt[a + b*x]*(15*a^3*d^3*(c + d*x) + a^2*b*d^2*(-839*c^2 - 337*c*d*x + 1 18*d^2*x^2) + a*b^2*d*(1785*c^3 + 637*c^2*d*x - 244*c*d^2*x^2 + 136*d^3*x^ 3) - 3*b^3*(315*c^4 + 105*c^3*d*x - 42*c^2*d^2*x^2 + 24*c*d^3*x^3 - 16*d^4 *x^4)))/(192*b*d^5*Sqrt[c + d*x]) + (5*(b*c - a*d)^2*(63*b^2*c^2 - 14*a*b* c*d - a^2*d^2)*ArcTanh[(Sqrt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[c + d*x])])/( 64*b^(3/2)*d^(11/2))
Time = 0.34 (sec) , antiderivative size = 271, normalized size of antiderivative = 0.88, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {100, 27, 90, 60, 60, 60, 66, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {x^2 (a+b x)^{5/2}}{(c+d x)^{3/2}} \, dx\) |
| \(\Big \downarrow \) 100 |
| \(\displaystyle \frac {2 c^2 (a+b x)^{7/2}}{d^2 \sqrt {c+d x} (b c-a d)}-\frac {2 \int \frac {(a+b x)^{5/2} (c (7 b c-a d)-d (b c-a d) x)}{2 \sqrt {c+d x}}dx}{d^2 (b c-a d)}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {2 c^2 (a+b x)^{7/2}}{d^2 \sqrt {c+d x} (b c-a d)}-\frac {\int \frac {(a+b x)^{5/2} (c (7 b c-a d)-d (b c-a d) x)}{\sqrt {c+d x}}dx}{d^2 (b c-a d)}\) |
| \(\Big \downarrow \) 90 |
| \(\displaystyle \frac {2 c^2 (a+b x)^{7/2}}{d^2 \sqrt {c+d x} (b c-a d)}-\frac {\frac {\left (-a^2 d^2-14 a b c d+63 b^2 c^2\right ) \int \frac {(a+b x)^{5/2}}{\sqrt {c+d x}}dx}{8 b}-\frac {(a+b x)^{7/2} \sqrt {c+d x} (b c-a d)}{4 b}}{d^2 (b c-a d)}\) |
| \(\Big \downarrow \) 60 |
| \(\displaystyle \frac {2 c^2 (a+b x)^{7/2}}{d^2 \sqrt {c+d x} (b c-a d)}-\frac {\frac {\left (-a^2 d^2-14 a b c d+63 b^2 c^2\right ) \left (\frac {(a+b x)^{5/2} \sqrt {c+d x}}{3 d}-\frac {5 (b c-a d) \int \frac {(a+b x)^{3/2}}{\sqrt {c+d x}}dx}{6 d}\right )}{8 b}-\frac {(a+b x)^{7/2} \sqrt {c+d x} (b c-a d)}{4 b}}{d^2 (b c-a d)}\) |
| \(\Big \downarrow \) 60 |
| \(\displaystyle \frac {2 c^2 (a+b x)^{7/2}}{d^2 \sqrt {c+d x} (b c-a d)}-\frac {\frac {\left (-a^2 d^2-14 a b c d+63 b^2 c^2\right ) \left (\frac {(a+b x)^{5/2} \sqrt {c+d x}}{3 d}-\frac {5 (b c-a d) \left (\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 d}-\frac {3 (b c-a d) \int \frac {\sqrt {a+b x}}{\sqrt {c+d x}}dx}{4 d}\right )}{6 d}\right )}{8 b}-\frac {(a+b x)^{7/2} \sqrt {c+d x} (b c-a d)}{4 b}}{d^2 (b c-a d)}\) |
| \(\Big \downarrow \) 60 |
| \(\displaystyle \frac {2 c^2 (a+b x)^{7/2}}{d^2 \sqrt {c+d x} (b c-a d)}-\frac {\frac {\left (-a^2 d^2-14 a b c d+63 b^2 c^2\right ) \left (\frac {(a+b x)^{5/2} \sqrt {c+d x}}{3 d}-\frac {5 (b c-a d) \left (\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 d}-\frac {3 (b c-a d) \left (\frac {\sqrt {a+b x} \sqrt {c+d x}}{d}-\frac {(b c-a d) \int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}}dx}{2 d}\right )}{4 d}\right )}{6 d}\right )}{8 b}-\frac {(a+b x)^{7/2} \sqrt {c+d x} (b c-a d)}{4 b}}{d^2 (b c-a d)}\) |
| \(\Big \downarrow \) 66 |
| \(\displaystyle \frac {2 c^2 (a+b x)^{7/2}}{d^2 \sqrt {c+d x} (b c-a d)}-\frac {\frac {\left (-a^2 d^2-14 a b c d+63 b^2 c^2\right ) \left (\frac {(a+b x)^{5/2} \sqrt {c+d x}}{3 d}-\frac {5 (b c-a d) \left (\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 d}-\frac {3 (b c-a d) \left (\frac {\sqrt {a+b x} \sqrt {c+d x}}{d}-\frac {(b c-a d) \int \frac {1}{b-\frac {d (a+b x)}{c+d x}}d\frac {\sqrt {a+b x}}{\sqrt {c+d x}}}{d}\right )}{4 d}\right )}{6 d}\right )}{8 b}-\frac {(a+b x)^{7/2} \sqrt {c+d x} (b c-a d)}{4 b}}{d^2 (b c-a d)}\) |
| \(\Big \downarrow \) 221 |
| \(\displaystyle \frac {2 c^2 (a+b x)^{7/2}}{d^2 \sqrt {c+d x} (b c-a d)}-\frac {\frac {\left (-a^2 d^2-14 a b c d+63 b^2 c^2\right ) \left (\frac {(a+b x)^{5/2} \sqrt {c+d x}}{3 d}-\frac {5 (b c-a d) \left (\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 d}-\frac {3 (b c-a d) \left (\frac {\sqrt {a+b x} \sqrt {c+d x}}{d}-\frac {(b c-a d) \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{\sqrt {b} d^{3/2}}\right )}{4 d}\right )}{6 d}\right )}{8 b}-\frac {(a+b x)^{7/2} \sqrt {c+d x} (b c-a d)}{4 b}}{d^2 (b c-a d)}\) |
(2*c^2*(a + b*x)^(7/2))/(d^2*(b*c - a*d)*Sqrt[c + d*x]) - (-1/4*((b*c - a* d)*(a + b*x)^(7/2)*Sqrt[c + d*x])/b + ((63*b^2*c^2 - 14*a*b*c*d - a^2*d^2) *(((a + b*x)^(5/2)*Sqrt[c + d*x])/(3*d) - (5*(b*c - a*d)*(((a + b*x)^(3/2) *Sqrt[c + d*x])/(2*d) - (3*(b*c - a*d)*((Sqrt[a + b*x]*Sqrt[c + d*x])/d - ((b*c - a*d)*ArcTanh[(Sqrt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[c + d*x])])/(Sq rt[b]*d^(3/2))))/(4*d)))/(6*d)))/(8*b))/(d^2*(b*c - a*d))
3.7.82.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Simp[ 2 Subst[Int[1/(b - d*x^2), x], x, Sqrt[a + b*x]/Sqrt[c + d*x]], x] /; Fre eQ[{a, b, c, d}, x] && !GtQ[c - a*(d/b), 0]
Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p _.), x_] :> Simp[b*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(d*f*(n + p + 2))), x] + Simp[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(d*f*(n + p + 2)) Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2, 0]
Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^( p_), x_] :> Simp[(b*c - a*d)^2*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(d^2*(d *e - c*f)*(n + 1))), x] - Simp[1/(d^2*(d*e - c*f)*(n + 1)) Int[(c + d*x)^ (n + 1)*(e + f*x)^p*Simp[a^2*d^2*f*(n + p + 2) + b^2*c*(d*e*(n + 1) + c*f*( p + 1)) - 2*a*b*d*(d*e*(n + 1) + c*f*(p + 1)) - b^2*d*(d*e - c*f)*(n + 1)*x , x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && (LtQ[n, -1] || (EqQ[n + p + 3, 0] && NeQ[n, -1] && (SumSimplerQ[n, 1] || !SumSimplerQ[p, 1])))
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Leaf count of result is larger than twice the leaf count of optimal. \(960\) vs. \(2(267)=534\).
Time = 1.61 (sec) , antiderivative size = 961, normalized size of antiderivative = 3.11
| method | result | size |
| default | \(-\frac {\sqrt {b x +a}\, \left (-96 b^{3} d^{4} x^{4} \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}-272 a \,b^{2} d^{4} x^{3} \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}+144 b^{3} c \,d^{3} x^{3} \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}+15 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{4} d^{5} x +180 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{3} b c \,d^{4} x -1350 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{2} b^{2} c^{2} d^{3} x +2100 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a \,b^{3} c^{3} d^{2} x -945 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) b^{4} c^{4} d x -236 a^{2} b \,d^{4} x^{2} \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}+488 a \,b^{2} c \,d^{3} x^{2} \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}-252 b^{3} c^{2} d^{2} x^{2} \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}+15 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{4} c \,d^{4}+180 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{3} b \,c^{2} d^{3}-1350 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{2} b^{2} c^{3} d^{2}+2100 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a \,b^{3} c^{4} d -945 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) b^{4} c^{5}-30 a^{3} d^{4} x \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}+674 a^{2} b c \,d^{3} x \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}-1274 a \,b^{2} c^{2} d^{2} x \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}+630 b^{3} c^{3} d x \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}-30 a^{3} c \,d^{3} \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}+1678 a^{2} b \,c^{2} d^{2} \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}-3570 a \,b^{2} c^{3} d \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}+1890 b^{3} c^{4} \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}\right )}{384 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, \sqrt {d x +c}\, b \,d^{5}}\) | \(961\) |
-1/384*(b*x+a)^(1/2)*(-96*b^3*d^4*x^4*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)- 272*a*b^2*d^4*x^3*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)+144*b^3*c*d^3*x^3*(b *d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)+15*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^( 1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^4*d^5*x+180*ln(1/2*(2*b*d*x+2*((b *x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^3*b*c*d^4*x-1350* ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2) )*a^2*b^2*c^2*d^3*x+2100*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^( 1/2)+a*d+b*c)/(b*d)^(1/2))*a*b^3*c^3*d^2*x-945*ln(1/2*(2*b*d*x+2*((b*x+a)* (d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*b^4*c^4*d*x-236*a^2*b*d^4 *x^2*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)+488*a*b^2*c*d^3*x^2*(b*d)^(1/2)*( (b*x+a)*(d*x+c))^(1/2)-252*b^3*c^2*d^2*x^2*(b*d)^(1/2)*((b*x+a)*(d*x+c))^( 1/2)+15*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b* d)^(1/2))*a^4*c*d^4+180*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1 /2)+a*d+b*c)/(b*d)^(1/2))*a^3*b*c^2*d^3-1350*ln(1/2*(2*b*d*x+2*((b*x+a)*(d *x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^2*b^2*c^3*d^2+2100*ln(1/2 *(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a*b^ 3*c^4*d-945*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c) /(b*d)^(1/2))*b^4*c^5-30*a^3*d^4*x*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)+674 *a^2*b*c*d^3*x*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)-1274*a*b^2*c^2*d^2*x*(b *d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)+630*b^3*c^3*d*x*(b*d)^(1/2)*((b*x+a)*...
Time = 0.51 (sec) , antiderivative size = 796, normalized size of antiderivative = 2.58 \[ \int \frac {x^2 (a+b x)^{5/2}}{(c+d x)^{3/2}} \, dx=\left [-\frac {15 \, {\left (63 \, b^{4} c^{5} - 140 \, a b^{3} c^{4} d + 90 \, a^{2} b^{2} c^{3} d^{2} - 12 \, a^{3} b c^{2} d^{3} - a^{4} c d^{4} + {\left (63 \, b^{4} c^{4} d - 140 \, a b^{3} c^{3} d^{2} + 90 \, a^{2} b^{2} c^{2} d^{3} - 12 \, a^{3} b c d^{4} - a^{4} d^{5}\right )} x\right )} \sqrt {b d} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} - 4 \, {\left (2 \, b d x + b c + a d\right )} \sqrt {b d} \sqrt {b x + a} \sqrt {d x + c} + 8 \, {\left (b^{2} c d + a b d^{2}\right )} x\right ) - 4 \, {\left (48 \, b^{4} d^{5} x^{4} - 945 \, b^{4} c^{4} d + 1785 \, a b^{3} c^{3} d^{2} - 839 \, a^{2} b^{2} c^{2} d^{3} + 15 \, a^{3} b c d^{4} - 8 \, {\left (9 \, b^{4} c d^{4} - 17 \, a b^{3} d^{5}\right )} x^{3} + 2 \, {\left (63 \, b^{4} c^{2} d^{3} - 122 \, a b^{3} c d^{4} + 59 \, a^{2} b^{2} d^{5}\right )} x^{2} - {\left (315 \, b^{4} c^{3} d^{2} - 637 \, a b^{3} c^{2} d^{3} + 337 \, a^{2} b^{2} c d^{4} - 15 \, a^{3} b d^{5}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{768 \, {\left (b^{2} d^{7} x + b^{2} c d^{6}\right )}}, -\frac {15 \, {\left (63 \, b^{4} c^{5} - 140 \, a b^{3} c^{4} d + 90 \, a^{2} b^{2} c^{3} d^{2} - 12 \, a^{3} b c^{2} d^{3} - a^{4} c d^{4} + {\left (63 \, b^{4} c^{4} d - 140 \, a b^{3} c^{3} d^{2} + 90 \, a^{2} b^{2} c^{2} d^{3} - 12 \, a^{3} b c d^{4} - a^{4} d^{5}\right )} x\right )} \sqrt {-b d} \arctan \left (\frac {{\left (2 \, b d x + b c + a d\right )} \sqrt {-b d} \sqrt {b x + a} \sqrt {d x + c}}{2 \, {\left (b^{2} d^{2} x^{2} + a b c d + {\left (b^{2} c d + a b d^{2}\right )} x\right )}}\right ) - 2 \, {\left (48 \, b^{4} d^{5} x^{4} - 945 \, b^{4} c^{4} d + 1785 \, a b^{3} c^{3} d^{2} - 839 \, a^{2} b^{2} c^{2} d^{3} + 15 \, a^{3} b c d^{4} - 8 \, {\left (9 \, b^{4} c d^{4} - 17 \, a b^{3} d^{5}\right )} x^{3} + 2 \, {\left (63 \, b^{4} c^{2} d^{3} - 122 \, a b^{3} c d^{4} + 59 \, a^{2} b^{2} d^{5}\right )} x^{2} - {\left (315 \, b^{4} c^{3} d^{2} - 637 \, a b^{3} c^{2} d^{3} + 337 \, a^{2} b^{2} c d^{4} - 15 \, a^{3} b d^{5}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{384 \, {\left (b^{2} d^{7} x + b^{2} c d^{6}\right )}}\right ] \]
[-1/768*(15*(63*b^4*c^5 - 140*a*b^3*c^4*d + 90*a^2*b^2*c^3*d^2 - 12*a^3*b* c^2*d^3 - a^4*c*d^4 + (63*b^4*c^4*d - 140*a*b^3*c^3*d^2 + 90*a^2*b^2*c^2*d ^3 - 12*a^3*b*c*d^4 - a^4*d^5)*x)*sqrt(b*d)*log(8*b^2*d^2*x^2 + b^2*c^2 + 6*a*b*c*d + a^2*d^2 - 4*(2*b*d*x + b*c + a*d)*sqrt(b*d)*sqrt(b*x + a)*sqrt (d*x + c) + 8*(b^2*c*d + a*b*d^2)*x) - 4*(48*b^4*d^5*x^4 - 945*b^4*c^4*d + 1785*a*b^3*c^3*d^2 - 839*a^2*b^2*c^2*d^3 + 15*a^3*b*c*d^4 - 8*(9*b^4*c*d^ 4 - 17*a*b^3*d^5)*x^3 + 2*(63*b^4*c^2*d^3 - 122*a*b^3*c*d^4 + 59*a^2*b^2*d ^5)*x^2 - (315*b^4*c^3*d^2 - 637*a*b^3*c^2*d^3 + 337*a^2*b^2*c*d^4 - 15*a^ 3*b*d^5)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(b^2*d^7*x + b^2*c*d^6), -1/384*( 15*(63*b^4*c^5 - 140*a*b^3*c^4*d + 90*a^2*b^2*c^3*d^2 - 12*a^3*b*c^2*d^3 - a^4*c*d^4 + (63*b^4*c^4*d - 140*a*b^3*c^3*d^2 + 90*a^2*b^2*c^2*d^3 - 12*a ^3*b*c*d^4 - a^4*d^5)*x)*sqrt(-b*d)*arctan(1/2*(2*b*d*x + b*c + a*d)*sqrt( -b*d)*sqrt(b*x + a)*sqrt(d*x + c)/(b^2*d^2*x^2 + a*b*c*d + (b^2*c*d + a*b* d^2)*x)) - 2*(48*b^4*d^5*x^4 - 945*b^4*c^4*d + 1785*a*b^3*c^3*d^2 - 839*a^ 2*b^2*c^2*d^3 + 15*a^3*b*c*d^4 - 8*(9*b^4*c*d^4 - 17*a*b^3*d^5)*x^3 + 2*(6 3*b^4*c^2*d^3 - 122*a*b^3*c*d^4 + 59*a^2*b^2*d^5)*x^2 - (315*b^4*c^3*d^2 - 637*a*b^3*c^2*d^3 + 337*a^2*b^2*c*d^4 - 15*a^3*b*d^5)*x)*sqrt(b*x + a)*sq rt(d*x + c))/(b^2*d^7*x + b^2*c*d^6)]
\[ \int \frac {x^2 (a+b x)^{5/2}}{(c+d x)^{3/2}} \, dx=\int \frac {x^{2} \left (a + b x\right )^{\frac {5}{2}}}{\left (c + d x\right )^{\frac {3}{2}}}\, dx \]
Exception generated. \[ \int \frac {x^2 (a+b x)^{5/2}}{(c+d x)^{3/2}} \, dx=\text {Exception raised: ValueError} \]
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(a*d-b*c>0)', see `assume?` for m ore detail
Time = 0.39 (sec) , antiderivative size = 378, normalized size of antiderivative = 1.22 \[ \int \frac {x^2 (a+b x)^{5/2}}{(c+d x)^{3/2}} \, dx=\frac {{\left ({\left (2 \, {\left (b x + a\right )} {\left (4 \, {\left (b x + a\right )} {\left (\frac {6 \, {\left (b x + a\right )}}{d {\left | b \right |}} - \frac {9 \, b^{3} c d^{7} + 7 \, a b^{2} d^{8}}{b^{2} d^{9} {\left | b \right |}}\right )} + \frac {63 \, b^{4} c^{2} d^{6} - 14 \, a b^{3} c d^{7} - a^{2} b^{2} d^{8}}{b^{2} d^{9} {\left | b \right |}}\right )} - \frac {5 \, {\left (63 \, b^{5} c^{3} d^{5} - 77 \, a b^{4} c^{2} d^{6} + 13 \, a^{2} b^{3} c d^{7} + a^{3} b^{2} d^{8}\right )}}{b^{2} d^{9} {\left | b \right |}}\right )} {\left (b x + a\right )} - \frac {15 \, {\left (63 \, b^{6} c^{4} d^{4} - 140 \, a b^{5} c^{3} d^{5} + 90 \, a^{2} b^{4} c^{2} d^{6} - 12 \, a^{3} b^{3} c d^{7} - a^{4} b^{2} d^{8}\right )}}{b^{2} d^{9} {\left | b \right |}}\right )} \sqrt {b x + a}}{192 \, \sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d}} - \frac {5 \, {\left (63 \, b^{4} c^{4} - 140 \, a b^{3} c^{3} d + 90 \, a^{2} b^{2} c^{2} d^{2} - 12 \, a^{3} b c d^{3} - a^{4} d^{4}\right )} \log \left ({\left | -\sqrt {b d} \sqrt {b x + a} + \sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d} \right |}\right )}{64 \, \sqrt {b d} d^{5} {\left | b \right |}} \]
1/192*((2*(b*x + a)*(4*(b*x + a)*(6*(b*x + a)/(d*abs(b)) - (9*b^3*c*d^7 + 7*a*b^2*d^8)/(b^2*d^9*abs(b))) + (63*b^4*c^2*d^6 - 14*a*b^3*c*d^7 - a^2*b^ 2*d^8)/(b^2*d^9*abs(b))) - 5*(63*b^5*c^3*d^5 - 77*a*b^4*c^2*d^6 + 13*a^2*b ^3*c*d^7 + a^3*b^2*d^8)/(b^2*d^9*abs(b)))*(b*x + a) - 15*(63*b^6*c^4*d^4 - 140*a*b^5*c^3*d^5 + 90*a^2*b^4*c^2*d^6 - 12*a^3*b^3*c*d^7 - a^4*b^2*d^8)/ (b^2*d^9*abs(b)))*sqrt(b*x + a)/sqrt(b^2*c + (b*x + a)*b*d - a*b*d) - 5/64 *(63*b^4*c^4 - 140*a*b^3*c^3*d + 90*a^2*b^2*c^2*d^2 - 12*a^3*b*c*d^3 - a^4 *d^4)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b* d)))/(sqrt(b*d)*d^5*abs(b))
Timed out. \[ \int \frac {x^2 (a+b x)^{5/2}}{(c+d x)^{3/2}} \, dx=\int \frac {x^2\,{\left (a+b\,x\right )}^{5/2}}{{\left (c+d\,x\right )}^{3/2}} \,d x \]